by Vaggelis Atlasis
What is a Light Clock?
To help explain
time dilation we will use a light clock (see Figure 1). A light clock is
a clock comprised of two parallel mirrors a length L away from each
other. They reflect a beam of light between them. For a full tick of the clock,
the light beam starts at the bottom mirror, reaches the top one and is
reflected back at the bottom mirror.
 |
A light clock; c indicates the speed of the light rays |
The Situation
Bob, stationary, has a light clock at his possession.
Alice is in a spaceship, moving at a constant velocity v, and has an identical clock that is synchronised to Bob’s. Both Bob and Alice perceive themselves
to be stationary and their respective counterpart moving in a certain direction;
Bob sees Alice and her clock moving at v with respect to him and Alice
sees Bob and his clock (as well as the Earth) moving at -v with respect
to her.
 |
Bob on Earth, with his clock, observing Alice travel to the right in her spaceship, with her clock, with velocity v. |
From Alice’s perspective, her clock is stationary and the
time for a tick of her clock (ΔtickA)
is equal to the distance travelled by light from the bottom mirror to the top
one and back (2L) divided by its speed (c). However, from Bob’s perspective
Alice’s clock is moving and the time for a tick of the moving clock (ΔtickB)
will be different. As the light clock is constantly moving, by the time the
light beam, travels the distance L, the top mirror will have moved some distance. Therefore,
for the light to reach the top mirror it has to travel diagonally. Similarly to
ΔtickA, ΔtickB
will be equal to the distance travelled by light from the bottom to the top
mirror and back divided by its speed. The distance travelled by light will not
be 2L as light is travelling diagonally, not vertically. Instead, we will let
this distance be 2D.
 |
Alice's and Bob's clock from their respective frames of reference (perspective). For the moving clocks, snapshots have been taken at the points where light touches the mirrors (note how depending on the direction of travel the light rays travel in different directions). |
Calculating the
Relationship Between ΔtickA & ΔtickB (& Deriving the Lorentz Factor)
 |
Alice's clock as Bob sees it. L represents the distance between the mirrors, D represents the distance light travels from the bottom to the top mirror (and vice versa). Finally, X represents the horizontal distance the mirrors travel within one tick of the clock. |
We can calculate D using the Pythagorean
theorem (a2 + b2 = c2). We know the vertical
distance between the mirrors is L. The diagonal distance light travels from
the bottom to the top mirror and vice versa is D, and the distance the bottom mirror moves in the time span of one tick of the clock (from Bob’s
perspective), is X.
Hence, we end up with
D2 =
L2 + X2.
By using the equation distance = velocity x time we find
that
X = vΔtickB,
where v is the velocity of the spaceship and ΔtickB
is the time for one tick of Alice’s clock from Bob’s perspective. We can also
rearrange the previous equation
ΔtickA
= 2L/c into L = c(ΔtickA)/2
and
ΔtickB
= 2D/c into D = c(ΔtickB)/2.
Finally, by substituting these equations into the Pythagorean
theorem equation, we end up with:
(c(ΔtickA)/2)2
+ (vΔtickB/2)2
= (c(ΔtickB)/2)2
We can then simplify and rearrange this equation to
find a relationship between ΔtickA
and ΔtickB.
c2ΔtickA2/4
+ v2ΔtickB2/4
= c2ΔtickB2/4
c2ΔtickA2
= c2ΔtickB2 –
v2ΔtickB2
c2ΔtickA2
= ΔtickB2(c2
– v2)
ΔtickB
= √(c2ΔtickA2/(c2
– v2))
ΔtickB
= cΔtickA/√(c2-v2)
ΔtickB
= ΔtickA x c/√c2(1
– v2/c2)
ΔtickB
= ΔtickA x c/c√(1 – v2/c2)
ΔtickB = 1/√(1 – v2/c2)
x ΔtickA
The T1/√(1 – c2/v2)
component of the equation is known as
the Lorentz Factor (γ). The velocity at which the “clock” travels with influences the Lorentz
factor in the following ways:
-
For v = 0, ΔtickB
= ΔtickA as none of the objects are moving and
the Lorentz factor is equal to one.
-
For 0 < v < c, γ takes
a finite value larger than 1. For example, when v = 0.5c, γ =
1,2 and when v = 0.999c, γ = 71. When v
= 0.99999c, γ = 223.61
-
For v >= c, γ is
either undefined or takes no real value. This shows us that no object with mass
can reach the speed of light as well as that the speed of light is the natural
speed limit.
Finding the Equation for
Time Dilation
From the section above, we’ve concluded that
Δtickmoving
= γΔtickstationary .
By “moving”
we mean an observer observing a moving clock and by “stationary” we mean an
observer observing a stationary clock (Alice) from their perspective. The equation effectively tells us that an observer measuring the time on a moving clock will observe every tick of the
clock take longer than an identical one at rest. We can find the relationship
between the time elapsed of a moving clock and a stationary one. Let’s say γ = 4.
In this case, the duration of a single tick of the moving clock corresponds to
the duration of 4 ticks of the stationary clock. If the duration of one tick is
5 seconds, the elapsed time on the moving clock will be 1 x 5 = 5 seconds and
the elapsed time on the stationary clock will be 4 x 5 = 20.
Hence, Δtmoving
= xΔtstationary (t
being time elapsed)
5 = 20x
x = ¼
= 1/γ
Therefore, we find that:
Δtmoving
= (1/γ)Δtstationary.
Conclusion (Moving Clocks
Run Slow)
Overall, we find that any “moving clock” (a moving
object) in an observer’s perspective will run slower than an identical stationary
clock, whether it is the observer’s or even if it is the same clock in another observer’s
frame of reference where the clock is stationary. This is known as time dilation
and is true for any moving object at a constant velocity, even if its
effects are too small to notice.